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Data on readership of a magazine indicates that the proportion of male readers over 30 years old is 0.30 and the proportion of male readers under 30 is 0.20. - Business Mathematics and Statistics

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प्रश्न

Data on readership of a magazine indicates that the proportion of male readers over 30 years old is 0.30 and the proportion of male readers under 30 is 0.20. If the proportion of readers under 30 is 0.80. What is the probability that a randomly selected male subscriber is under 30?

योग

उत्तर

Let E1 be the event of the subscriber is under 30 and E2 be the event of the subscriber is above 30.

Let B be the event of the subscriber is a male.

Given P(E1) = 0.80 and P(E2) = 1 − 0.8 = 0.2

and P`("B"/"E"_1)` = 20, P`("B"/"E"_2)` = 0.30

∴ `"P"("E"_1/"B") = ("P"("E"_1) xx "P"("B"/"E"_1))/("P"("E"_1) xx "P"("B"/"E"_1) + "P"("E"_2) xx "P"("B"/"E"_2))`

= `(0.80 xx 0.20)/(0.80 xx 0.20 + 0.20 xx 0.30)`

= `0.16/(0.16 + 0.06)`

= `0.16/0.22`

= `16/22`

∴ `"P"("E"_1/"B")` = 0.727

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अध्याय 8: Descriptive Statistics and Probability - Miscellaneous Problems [पृष्ठ २०६]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
अध्याय 8 Descriptive Statistics and Probability
Miscellaneous Problems | Q 9 | पृष्ठ २०६

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