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प्रश्न
Derive an expression for potential energy of a system of two point charges.
व्युत्पत्ति
उत्तर
- Electrostatic potential energy of a system of point charges is defined as the total amount of work done to assemble the system of charges by bringing them from infinity to their present locations.
- Let us consider 2 charges q1 and q2 with position vectors r1 and r2 relative to the origin.
- We consider the charges q1 and q2 initially at infinity and determine the work done by an external agency to bring the charges to the given locations.
-
In bringing the first charge q1 to position A(`barr_1`) no work is done because there is no external field against which work is no work is done because there is no external field against which work is required to be done as charge q2 is still at infinity i.e., W1 = 0. This charge produces a potential in space given by `V_l=1/(4piepsi_0)q_1/r_1`
where r1 is the distance of point A from the origin. -
When we bring charge q2 from infinity to B(`barr_2`) at a distance r12, from q1, work done is `W_2=("potential at B due to charge" q_1)xxq_2``=q_1/(4piepsi_0r_12)xxq_2,("where" AB = r_12)`
- This work done in bringing the two charges to their respective locations is stored as the potential energy of the configuration of two charges.
`U=1/(4piepsi_0)(q_1q_2)/r_12`
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