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Describe the Procedure to Measure the Diameter of a Wire with the Help of a Screw Gauge. - Physics

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प्रश्न

Describe the procedure to measure the diameter of a wire with the help of a screw gauge.

टिप्पणी लिखिए

उत्तर १

Measurement of diameter of wire with a screw gauge:

The wire whose thickness is to be determined is placed between the anvil and spindle end, the thimble is rotated until the wire is firmly held between the anvil and spindle. The rachet is provided to avoid excessive pressure on the wire. It prevents the spindle from further movement. The thickness of the wire could be determined from the reading as shown in the figure below.

The pitch of the screw = 1 mm

L.C. of screw gauge = 0.01 mm

Main scale reading = 2.5 mm

46th division of circular scale coincides with the base line.

Therefore, circular scale reading = 46 × 0.01 = 0.46 mm

Total reading = Main scale reading + circular scale reading

 = (2.5 + 0.46) mm

 = 2.96 mm

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उत्तर २

The following procedure is used to measure the diameter of a wire
(a). Calculate the least count and zero error of the screw gauge.
(b). Place the wire in between the studs. Turn the ratchet clockwise so as to hold the wire gently in between the studs. Record the main scale reading.
(c). Now record the division of circular scale that coincides with the baseline of the main scale. This circular scale division multiplied by the least count will give circular scale reading.
(d). The observed diameter is obtained by adding the circular scale reading to the main scale reading. Subtract the zero error if any, with its proper sign, from the observed diameter to get the true diameter.

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Vernier Callipers
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Measurements and Experimentation - Exercise 1 (B) [पृष्ठ २०]

APPEARS IN

सेलिना Concise Physics [English] Class 9 ICSE
अध्याय 1 Measurements and Experimentation
Exercise 1 (B) | Q 22 | पृष्ठ २०
फ्रैंक Physics [English] Class 9 ICSE
अध्याय 1 Measurement
Exercise 5 | Q 59 | पृष्ठ ४९

संबंधित प्रश्न

What is meant by zero error of vernier callipers ? How is it determined? Draw neat diagrams to explain it. How is it taken in account to get the correct measurement?


(a) A vernier scale has 20 divisions. It slides over the main scale, whose pitch is 0.5 mm. If the number of divisions on the left hand of the zero of vernier on the main scale is 38 and the 18th vernier scale division coincides with the main scale, calculate the diameter of the sphere, held in the jaws of vernier callipers.
(b) If the vernier has a negative error of 0.04 cm, calculate the corrected radius of the sphere.


What do you understand by the term zero error?


A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate

  1. pitch
  2. observed diameter
  3. least count
  4. corrected diameter.

Explain the term least count of a screw gauge. How are they determined?


What is the least count in the case of the following instrument?

vernier calipers


What is the difference between a nail and a screw?

A screw gauge has 50 divisions on its circular scale and the pitch of the screw is 0.5 mm. What us its least count?

What is meant by zero error of a vernier caliper? How is it determined? Draw neat diagrams to explain it. How is it taken into account to get the correct measurement?

The main scale reading while measuring the thickness of a rubber ball using Vernier caliper is 7 cm and the Vernier scale coincidence is 6. Find the radius of the ball.


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