Question

Design a class to overload the method display(.......) as follows: 

1. void display(String str, char ch): checks whether the word str contains the letter ch at the beginning as well as at the end or not. If present, print 'Special Word' otherwise print 'No special word'.
2. void display(String str1, String str2): checks and prints whether both the words are equal or not.
3. void display(String str, int n): prints the character present at n^th position in the word str. 

Write a suitable main() method. 

Answer 1

import java.util.*;
class FQ22{
void display(String str, char ch)
{char x, y;
x = str.charAt(0);
y = str.charAt(str.length() - 1);
if (x == ch && y == ch)
System.out.println("Tt is a Special word");
else
System.out.println("No Special Word");
}

void display(String str1, String str2)
{if (str1.equalsIgnoreCase(str2))
System.out.println("The Strings are equal");
else
System.out.println("The Strings are not equal");
}

void display(String str, int n)
{ System.out.println(str.charAt(n));
}

public static void main(String args[])
{FQ22 Q = new FQ22();
Scanner ob = new Scanner(System.in);
String a, b; 
char c;
int n;
System.out.println("1.Checking for Special Word");
System.out.println("2.Checking whether the words are equal or not");
System.out.println("3 Printing character at nth position");
System.out.println("Enter your choice...1/2/3");
switch(ob.nextInt())
{case 1: System.out.println("Enter a string followed by a character");
         a = ob.next();
         c = ob.next().charAt(0);
         Q.display(a, c); // METHOD CALL
         break;
case 2: System.out.println("Enter the two strings");
        a = ob.next();
        b = ob.next();
        Q.display(a, b); // METHOD CALL
        break;

case 3: System.out.println("Enter the String and the position");
        a = ob.next();
        n = ob.nextInt();
        Q.display(a, n); // METHOD CALL
        break;

default: System.out.println("Invalid choice");
}}}