Advertisements
Advertisements
प्रश्न
Determine the nature of the roots of the following quadratic equation :
x2 -4x + 4=0
उत्तर
x2 -4x + 4=0
b2 - 4ac
= (-4)2- 4(1)(4)
= 16- 16
=0
Since discriminant is 01 hence the roots are real and equal .
APPEARS IN
संबंधित प्रश्न
If (k – 3), (2k + l) and (4k + 3) are three consecutive terms of an A.P., find the value of k.
Find the values of k for which the roots are real and equal in each of the following equation:
5x2 - 4x + 2 + k(4x2 - 2x - 1) = 0
Determine the nature of the roots of the following quadratic equation :
2x2 + 5x - 6 = 0
Solve the following quadratic equation using formula method only
5x2 - 19x + 17 = 0
Solve the following quadratic equation using formula method only
`3"x"^2 +2 sqrt 5 "x" -5 = 0`
If one root of the equation 2x² – px + 4 = 0 is 2, find the other root. Also find the value of p.
If a is a root of the equation x2 – (a + b)x + k = 0, find the value of k.
If the roots of the given quadratic equation are real and equal, then find the value of ‘m’.
(m – 12)x2 + 2(m – 12)x + 2 = 0
Which of the following equations has two distinct real roots?
Solve for x: 9x2 – 6px + (p2 – q2) = 0
