Question

Determine the distance from the origin to the plane in the following case x + y + z = 1

विकल्प

• `sqrt(3)`

• `1/sqrt(3)`

• 2

• `5/sqrt(14)`

Answer 1

`1/sqrt(3)`

Explanation:

Direction ratios of the normal to the plane axt by = d are (a, b, c) perpendicular from the origin to the plane = `d/(sqrt(a^2 + b^2 + c^2)`

Distance from the origin = `1/sqrt(1^2 + 1^2 + 1^2) = 1/sqrt(3)`