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प्रश्न
Determine the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case.
उत्तर
We have,
2 |
3, 4, 5 |
2 |
3, 2, 5 |
3 |
3, 1, 5 |
5 |
1, 1, 5 |
1, 1, 1 |
Since, the LCM of 3, 4 and 5 is 2 × 2 × 3 × 5 = 60.
∴ The required number is 6 is the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case.
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संबंधित प्रश्न
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| Column I | Column II |
| (i) The difference of two consecutive whole numbers |
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