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प्रश्न
Determine the nature of roots of the following quadratic equation.
2y2 – 7y + 2 = 0
उत्तर
2y2 – 7y + 2 = 0
Comparing 2y2 − 7y + 2 = 0 with the standard form ay2 + by + c = 0.
a = 2, b = – 7, c = 2
Δ = b2 − 4ac
Δ = (– 7)2 − 4(2)(2)
Δ = 49 − 16
Δ = 33
Since the discriminant > 0 so, the roots of the given quadratic equation are real and unequal.
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