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рдкреНрд░рд╢реНрди
Determine the value of R for maximum power transfer and find the value of maximum transfer.
рдЙрддреНрддрд░
(1) Calculation of ЁЭСЙЁЭСЗЁЭР╗
Removing the variable resistor R from the network
Mesh 1 and 2 will form A loop.
Writing current equation for the loop.
ЁЭР╝2−ЁЭР╝1=4 ………………..(1)
Applying KVL to the loop,
8−ЁЭР╝1−5ЁЭР╝1−5ЁЭР╝2−10=0
−6ЁЭР╝1−5ЁЭР╝2=2 ………..(2)
From (1) and (2) we get,
ЁЭР╝1=−2ЁЭР┤ and ЁЭР╝2=2ЁЭР┤
Writing ЁЭСЙЁЭСЗЁЭР╗ equation,
8−ЁЭР╝1−ЁЭСЙЁЭСЗЁЭР╗=0 => 8+2−ЁЭСЙЁЭСЗЁЭР╗=0
ЁЭРХЁЭРУЁЭРЗ=ЁЭЯПЁЭЯОЁЭРХ
(2) Calculation of ЁЭСЕЁЭСЗЁЭР╗
Replacing the voltage source by short circuits and current sources by an open circuit
ЁЭСЕЁЭСЗЁЭР╗ = 10Ω || 1Ω = 0.91Ω
For maximum power transfer
(3) Calculation of ЁЭСГЁЭСЪЁЭСОЁЭСе
`P_(max)=(V_(TH)^2)/(4R_(TH))=10^2/(4xx0.91)=27.47w`