हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा १२

Discuss the source of electromagnetic waves. - Physics

Advertisements
Advertisements

प्रश्न

Discuss the source of electromagnetic waves.

संक्षेप में उत्तर

उत्तर

Any stationary source charge produces only an electric field. When the charge moves with uniform velocity, it produces a steady current which gives rise to a magnetic field (not time-dependent, only space-dependent) around the conductor in which charge flows.

If the charged particle accelerates, in addition to the electric field it also produces a magnetic field. Both electric and magnetic fields are time-varying fields. Since the electromagnetic waves are transverse waves, the direction of propagation of electromagnetic waves is perpendicular to the plane containing electric and magnetic field vectors.

Any oscillatory motion is also an accelerating motion, so, when the charge oscillates (oscillating molecular dipole) about their mean position, it produces electromagnetic waves.

Suppose the electromagnetic field in free space propagates along z-direction, and if the electric field vector points along y-axis then the magnetic field vector will be mutually perpendicular to both electric field and the propagation vector direction,
which means
Ey = E0 sin (kz – ωt)
Bx = B0 sin (kz – ωt)
Where, E0 and B0 are amplitude of the oscillating electric and magnetic field, k is a wave number, ω is the angular frequency of the wave and k^ (unit vector, here it is called propagation vector) denotes the direction of propagation of electromagnetic wave.

Note that both electric field and magnetic field oscillate with a frequency (frequency of the electromagnetic wave) which is equal to the frequency of the source (here, the oscillating charge is the source for the production of electromagnetic waves). In free space or in a vacuum, the ratio between E0 and B0 is equal to the speed of the electromagnetic wave, which is equal to the speed of light c.

c = `"E"_0/"B"_0`

In any medium, the ratio of E0 and B0 is equal to the speed of electromagnetic wave in that medium, mathematically, it can be written as

v = `"E"_0/"B"_0` < c

Further, the energy of electromagnetic waves comes from the energy of the oscillating charge.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Electromagnetic waves - Evaluation [पृष्ठ २८३]

APPEARS IN

सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 5 Electromagnetic waves
Evaluation | Q III. 7. | पृष्ठ २८३
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×