Question

Divide 24(x²yz + xy²z + xyz²) by 8xyz using both the methods.

Answer 1

24(x²yz + xy²z + xyz²) 

`= 2 xx 2 xx 2 xx 3 xx[(x xx x xx y xx z) + (x xx y xx y xx z) + (x xx y xx z xx z)]`

`= 2 xx 2 xx 2 xx 3 xx x xx y xx z  xx ( x + y + z) = 8 xx 3 xx xyz xx (x + y + z)` .....(By taking out the common factor)

Therefore,

24(x²yz + xy²z + xyz²) ÷ 8xyz

`= (8 xx 3 xx xyz xx (x + y + z))/(8 xx xyz)`

= 3 × (x + y + z)

= 3(x + y + z)

Alternately,

24(x²yz + xy²z + xyz²) ÷ 8xyz

`= (24x^2yz)/(8xyz) + (24xy^2z)/(8xyz) + (24xyz^2)/(8xyz)`

= 3x + 3y + 3z

= 3(x + y + z)