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Divide the following redox reaction into oxidation and reduction half-reaction. 2CuA+⟶Cu+CuA2+ - Chemistry

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प्रश्न

Divide the following redox reaction into oxidation and reduction half-reaction.

\[\ce{2Cu+ -> Cu + Cu^2+}\]

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उत्तर

Oxidation: \[\ce{Cu+ -> Cu^2+ + e-}\]

Reduction: \[\ce{Cu+ + e- -> Cu}\]

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