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प्रश्न
Does the point (–2.5, 3.5) lie inside, outside or on the circle x2 + y2 = 25?
योग
उत्तर
The equation of the given circle is x2 + y2 = 25.
x2 + y2 = 25
⇒ (x – 0)2 + (y – 0)2 = 52, which is of the form (x – h)2 + (y – k)2 = r2, where h = 0, k = 0, and r = 5.
∴Centre = (0, 0) and radius = 5
Distance between point (–2.5, 3.5) and centre (0, 0)
OP = `sqrt((-2.5 - 0)^2 + (3.5 - 0)^2)`
= `sqrt(6.25 + 12.25)`
= `sqrt18.50`
= 4.3 < 5
Since the distance between point (–2.5, 3.5) and centre (0, 0) of the circle is less than the radius of the circle, point (–2.5, 3.5) lies inside the circle.
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