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प्रश्न
Draw a line segment LM = 6.5 cm and take a point P not lying on it. Using a set square construct a line perpendicular to LM through P
उत्तर
Step 1: Draw a line LM = 6.5 cm and take a point X anywhere above the line LM.
Step 2: Place one of the arms of the right angle of a set square along with the line LM and the other arm of its right angle touches the point X.
Step 3: Draw a line through the point X meeting LM at Y.
Step 4: The line XY is perpendicular to the line LM at Y.
That is, LM ⊥ XY.
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संबंधित प्रश्न
Draw line l. Take point P anywhere outside the line. Using a set square, draw a line PQ perpendicular to line l.
Draw line AB. Take point M anywhere outside the line. Using a compass and ruler, draw a line MN perpendicular to line AB.
Draw any line segment `overline"AB"`. Mark any point M on it. Through M, draw a perpendicular to `overline"AB"`. (use ruler and compasses)
Draw any line segment `overline"PQ"`. Take any point R not on it. Through R, draw a perpendicular to `overline"PQ"`. (use ruler and set-square)
