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प्रश्न
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
5.6 cm
उत्तर
Construction:
Step 1: Drawn a line and marked two points A and B on it so that AB = 5.6 cm
Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of the same length, one above AB and one below AB
Step 3: With the same radius and B as centre drawn two arcs to cut the arcs drawn in step 2 and marked the points of intersection of the arcs as C and D
Step 4: Joined C and D. CD intersects AB. Marked the point of intersection as ‘O’.
CD is the required perpendicular bisector of AB.
Now ∠AOC = 90°
AO = BO
= 2.8 cm
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संबंधित प्रश्न
In each of the following, draw perpendicular through point P to the line segment AB :
(i)
(ii)
(iii)
Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From point P, draw a perpendicular to AB.
Only one perpendicular bisector can be drawn to a given line segment.
It is possible to draw two bisectors of a given angle.
Infinitely many perpendiculars can be drawn to a given ray.
Infinitely many perpendicular bisectors can be drawn to a given ray.
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