Question

Draw the graphs of the following equations on the same graph paper:

2x + 3y = 12,

x − y = 1

Answer 1

The given equations are

2x + 3y = 12 ......(i)

x − y = 1 .....(ii)

Putting x = 0 in equation (i) weget

=> 2 xx 0 + 3y = 12

=> y = 4

x = 0, y = 4

Putting y = 0 in equation (i) we get

`=> x + 3 xx 0 = 6`

`=> x = 6, y = 0

Use the following table to draw the graph.

x	0	6
y	4	0

Draw the graph by plotting the two points A(0,2) and B(6,0) from table

x - y = 1 .....(ii)

Putting x = 0 in eqaution (ii) we get

=> 0 - y = 1

=> y = -1

x = 0, y = -1

Putting y = 0 in equation (ii) we get

=> x - 0 = 1

=> x = 1

x = 1, y = 0

Use the following table to draw the graph.

x	0	1
y	-1	0

Draw the graph by plotting the two points C(0,-1), D(1,0) from table.

Draw the graph by plotting the two points from the table.

The intersection point is P(3, 2)

Three points of the triangle are A(0,4), C(0, -1) and P(3,2).

Hence the value of x = 3 and y = 2.