Question

`abs((1,1,1),("e",0,sqrt2),(2,2,2))` is equal to ____________.

विकल्प

• 0

• 2

• none of these

• 3e

Answer 1

`abs((1,1,1),("e",0,sqrt2),(2,2,2))` is equal to 0.

Explanation:

`abs((1,1,1),("e",0,sqrt2),(2,2,2)) = 2 abs((1,1,1),("e",0,sqrt2),(1,1,1)) = 0,` because, row 1 and row 3 are identical. Therefore determinant will be zero.