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प्रश्न
Evaluate: (50 + 6−1) × 33
योग
उत्तर
(50 + 6−1) × 33 = `(5^0 xx 3^3) + (6^(-1) xx 3^3)`
= `(1 xx 27) + (1/(2 xx 3) xx 3^3)`
= `27 + (1/2 xx 3^(3 - 1))`
= `27 + (1/2 xx 3^2)`
= `27 + 9/2`
= `(54 + 9)/2`
= `63/2`
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अध्याय 1: Numbers - Exercise 1.6 [पृष्ठ ४५]
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