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प्रश्न
Expand : `(2"x"-1/(2"x"))^2`
योग
उत्तर
`(2"x"-1/(2"x"))^2=(2"x")^2+(1/(2"x"))^2-2xx2"x"xx1/(2"x")`
`=4"x"^2+1/(4"x"^2)-2`
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Important Formula of Expansion
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