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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा ९

Expand the following: (2p + 3)(2p – 4)(2p – 5) - Mathematics

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प्रश्न

Expand the following:

(2p + 3)(2p – 4)(2p – 5)

योग

उत्तर

(2p + 3)(2p – 4)(2p – 5)

(x + a)(x + b)(x + c) ≡ x3 + (a + b + c) x2 + (ab + ba + ca) x + abc

(2p + 3)(2p – 4)(2p – 5) = (2p)3 + (3 – 4 – 5) (2p)2 + [(3 × – 4)2 + (– 4 × – 5) + (– 5 × 3)] 2p + 3 × – 4 × – 5

= 8p3 + (– 6) (4p2) + [–12 + 20 + (–15)] 2p + 60

= 8p3 – 24p2 + (–7)2p + 60

(2p + 3)(2p – 4)(2p – 5) = 8p3 – 24p2 – 14p + 60

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अध्याय 3: Algebra - Exercise 3.4 [पृष्ठ १०१]

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सामाचीर कलवी Mathematics [English] Class 9 TN Board
अध्याय 3 Algebra
Exercise 3.4 | Q 1. (iii) | पृष्ठ १०१
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