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प्रश्न
Explain analysis of crystal structure using Bragg’s X ray spectrometer
उत्तर
W.L Bragg’s explained the phenomenon of X-ray diffraction from a single crystal shown
as follows
When a beam of X-rays is incident on a crystal it is scattered by individual atoms of the rich atomic planes. Thus, each atom become a source of scattered radiation. The atomic planes responsible for the X-ray diffraction are called BRAGG’S PLANES. Therefore the sets of Braggs planes constitute the crystal grating. Bragg’s scattering or Bragg’s diffraction is also referred as Braggs reflection. Bragg derived a law called Bragg’s law to explain the X-ray diffraction effect.
Here a beam of X-ray is incident on a set of parallel planes of a crystal. The rays makes a
glancing angle θ and are practically reflected from different successive planes. The phase
relationship of the scattered rays can be determined from their path differences. Here two
parallel X-rays are reflected from two consecutive planes PI and P2. The path differences between then as shown
δ=MB+BN=2MB=2AB sinθ
Here AB = d,the interplanar spacing of the crystal.Hence,
δ=2dsinθ
The two diffracted rays reinforce each other when they interfere constructively when their path difference δ is equal to nλ
Hence, 2dsinθ=nλ
This is called Bragg’s law .
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संबंधित प्रश्न
Why X-rays are used to study the crystal structure?
‘Crystal acts as three dimensional grating for X-rays’, explain.
Derive Bragg's condition for X-ray diffraction. Monochromatic X rays are
incident on a crystal. If the first order rejection is observed at an angle of 3.4•, at
what angle would second order reflection expected.