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प्रश्न
Explain the continuity condition for a flow tube. Show that the flow speed is inversely proportional to the cross-sectional area of a flow tube.
उत्तर
Imagine a fluid flowing smoothly or steadily. Although the fluid's velocity in a flow tube is always parallel to the tube, its magnitude might vary. Assume that at points P and Q, the velocity is `vec(v)_1` and `vec(v)_2`, respectively. The mass of the fluid travelling through A1 in a unit of time is A1ρ1v1, and the mass passing through A2 in a unit of time is A2ρ2v2, assuming that A1 and A2 are the cross-sectional areas of the tube and that ρ1 and ρ2 are the fluid densities at these two sites. Since the tube's boundary is closed off to the flow of any fluid, the conservation of mass necessitates
A1ρ1v1 = A2ρ2v2 ...(1)
The equation of continuity of flow is represented by equation (1). It is valid for compressible fluids, which, like all gases, can have variable fluid densities at different points along a tube of flow. As with all liquids, an incompressible fluid has the simpler form ρ1 = ρ2 Eq. (1).
A1v1 = A2v2 ...(2)
∴ `v_1/v_2 = A_2/A_1` ...(3)
that is, the cross-sectional area of a flow tube and the flow speed are inversely related. The flow has a small pace in big areas and vice versa. The continuity equation for an incompressible fluid with constant density over the whole range is given by equation (2).