Advertisements
Advertisements
प्रश्न
Explain the octet rule for the formation of –
Sodium chloride from a sodium atom and a chlorine atom.
उत्तर
Formation of sodium chloride NaCl, Na atom has atomic number 11 [2, 8, 1], There is 1 electron in the outermost M shell it is not possible to gain 7 electrons and to lose 1 electron is easier, by losing sodium atom because of \[\ce{Na+}\] ion.
While Cl atomic number 17 [2, 8, 7] has 7 electrons in outermost M shell for Cl atom it is easier to gain 1 electron, becomes \[\ce{Cl-}\] ion.
By losing 1 electron and by gaining 1 electron both sodium and chlorine attain octet configuration and become stable and there is the electrostatic force that pulls them and becomes sodium chloride.
APPEARS IN
संबंधित प्रश्न
Which one of the following is a correct electronic configuration of sodium?
What is the maximum number of electrons which can be accommodated in the K shell of an atom?
Which of the following is the correct electronic configuration of sodium?
Which of the following represents the correct electron distribution in magnesium ion?
What is meant by the term orbits
What are ‘energy levels’?
Differentiate between the term Stable and unstable electronic configuration.
State true or false. If false, correct the statement.
The maximum number of electron in L Shell is 10.
For an atom ‘X’, K, L and M shells are completely filled. How many electrons will be present in it?
Write down the electron distribution of chlorine atom. How many electrons are there in the L shell? (Atomic number of chlorine is 17).