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प्रश्न
Factorise : 24a3 + 37a2 - 5a
योग
उत्तर
24a3 + 37a2 - 5a
= a( 24a2 + 37a - 5 )
= a( 24a2 + 40a -3a - 5 )
= a x [ 8a( 3a + 5 ) - 1( 3a + 5 )]
= a[( 8a - 1 )( 3a + 5 )]
= a( 8a - 1 )( 3a + 5 )
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