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प्रश्न
Factorise: `(7 3/10)^2 - (2 1/10)^2`
योग
उत्तर
`(7 3/10)^2 - (2 1/10)^2`
`= (73/10)^2 - (21/10)^2`
`= (73/10 + 21/10) (73/10 - 21/10)` ...[a2 – b2 = (a + b) (a – b)]
`= (94/10) (52/10)`
`= (47/5)(26/5) = 1222/25 = 48 22/25`
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Factorisation by Difference of Two Squares
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