Question

factorise: b(c - d)² + a(d - c) + 3(c - d)

Answer 1

b(c - d)² + a(d - c) + 3(c - d)

= b (c - d)² - a(c - d) + 3(c - d)

= (c - d) [b (c - d) - a + 3]

= (c - d) (bc - bd - a + 3)