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प्रश्न
Factorise the following by taking out the common factor
3y(x – 2)2 – 2(2 – x)
योग
उत्तर
3y(x – 2)2 – 2(2 – x) = 3y(x – 2)(x – 2) – 2(–1)(x – 2)
∵ Taking out – 1 from 2 – x
= 3y(x – 2)(x – 2) + 2(x – 2)
Taking out the binomial factor x – 2 from each term, we get
= (x – 2) ...[3y(x – 2) + 2]
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Factorisation by Taking Out the Common Binomial Factor from Each Term
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अध्याय 3: Algebra - Exercise 3.4 [पृष्ठ ९६]
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