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प्रश्न
Factorise the following expression.
`1/2"y"^2-8"z"^2`
उत्तर
`1/2"y"^2-8"z"^2`
= `1/2("y"^2-16"z"^2)`
= `1/2[("y")^2-(4"z")^2]`
= `1/2("y"+4"z")("y"-4"z")` ...[∵ a2 − b2 = (a + b) (a − b)]
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