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प्रश्न
Factorise the following expression.
121b2 − 88bc + 16c2
योग
उत्तर
121b2 − 88bc + 16c2
On writing it as follows:
(11b)2 − 2 × 11b × 4c + (4c)2
Using the identity a2 − 2ab + b2 = (a − b)2
= (11b − 4c)2
= (11b − 4c) (11b − 4c)
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