Advertisements
Advertisements
प्रश्न
Factorise the following.
p2 + 14p + 13
योग
उत्तर
We have,
p2 + 14p + 13 = p2 + 13p + p + 13 × 1
= p(p + 13) + 1(p + 13)
= (p + 13)(p + 1)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
APPEARS IN
संबंधित प्रश्न
Use a suitable identity to get the following products.
(2y + 5) (2y + 5)
Find the following squares by suing the identities.
`(2/3 m + 3/4 n)^2`
Simplify (7m − 8n)2 + (7m + 8n)2
Using identities, evaluate 712
Using identities, evaluate (5.2)2
Of which of the binomials given below is m2n2 + 14mnpq + 49p2q2 the expansion?
Use the formula to find the value.
54 × 46
Use a formula to multiply of (4z – 5y)(4z + 5y)
If a2 + b2 = 74 and ab = 35, then find a + b.
Factorise `x^2 + 1/x^2 + 2 - 3x - 3/x`.