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प्रश्न
Factorise the following.
y2 – 2y – 15
योग
उत्तर
We have,
y2 – 2y – 15 = y2 + (3 – 5)y – 15
= y2 + 3y – 5y – 15
= y(y + 3) – 5(y + 3)
= (y + 3)(y – 5)
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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
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