Advertisements
Advertisements
प्रश्न
Factorise using the grouping method :
x (6x - 5y) - 4 (6x - 5y)2
योग
उत्तर
x (6x - 5y) - 4 (6x - 5y)2
= (6x - 5y) [x - 4(6x - 5y)]
[Taking (6x - 5y) common from the three terms]
= (6x - 5y) (x - 24x + 20y)
= (6x - 5y) (-23x + 20y)
= (6x - 5y) (20y - 23x)
shaalaa.com
Factorisation by Grouping
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise by the grouping method : ab - 2b + a2 - 2a
Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`
Factorise using the grouping method :
a2 + 4b2 - 3a + 6b - 4ab
Factorise : xy - ay - ax + a2 + bx - ab
factorise: x2 - 10xy + 24y2
Factorise: 7b2 - 8b + 1
factorise: 1 - 18x - 63x2
factorise: (3x - 2y)2 - 5(3x - 2y) - 24
factorise: 1 - 3x - 3y - 4(x + y)2
Factorise the following by grouping the terms:
xy(a2 + 1) + a(x2 + y2)