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Factorise Using the Grouping Method: X (6x - 5y) - 4 (6x - 5y)2 - Mathematics

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प्रश्न

Factorise using the grouping method :
x (6x - 5y) - 4 (6x - 5y)2

योग

उत्तर

x (6x - 5y) - 4 (6x - 5y)2

= (6x - 5y) [x - 4(6x - 5y)]

[Taking (6x - 5y) common from the three terms]

= (6x - 5y) (x - 24x + 20y)

= (6x - 5y) (-23x + 20y)

= (6x - 5y) (20y - 23x)

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Factorisation by Grouping
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Factorisation - Exercise 5 (A) [पृष्ठ ६९]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 5 Factorisation
Exercise 5 (A) | Q 20 | पृष्ठ ६९
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