Advertisements
Advertisements
प्रश्न
Factorize (x + 2)(x2 + 25) -10x2 - 20x
उत्तर
= ( x + 2)(x2 + 25) -10x ( x + 2)
Taking ( x + 2) common in both terms
= (x + 2)(x2 + 25 -10x)
= ( x + 2)(x2 -10x + 25)
Splitting middle term of x2 -10x + 25
= ( x + 2){x2 - 5x - 5x + 25}
= ( x + 2){x ( x - 5) - 5( x - 5)}
= ( x + 2)( x - 5)( x - 5)
∴ ( x + 2)(x2 + 25) -10x2 - 20x = ( x + 2)( x - 5)( x - 5)
APPEARS IN
संबंधित प्रश्न
Factorize the following expressions:
1029 – 3x3
(3x - 2 y)3 + (2 y - 4z )3 + (4z - 3x)3
Find the value of x3 + y3 − 12xy + 64, when x + y =−4
If x3 − 3x2 + 3x − 7 = (x + 1) (ax2 + bx + c), then a + b + c =
Write the number of the term of the following polynomial.
ax – by + y x z
Multiply: (2x - 3y)(2x + 3y)
Divide: n2 - 2n + 1 by n - 1
The area of a rectangular field is 25x2 + 20xy + 3y2 square unit. If its length is 5x + 3y unit, find its breadth, Hence find its perimeter.
If x = 2 and y = 3, then find the value of the following expressions
2x – 3y
The value of 7a – 4b when a = 3, b = 2 is
