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प्रश्न
Fill in the following blank using suitable word:
The amount of heat required to change the state of a physical substance without any change of temperature is called .......... of the substance.
उत्तर
The amount of heat required to change the state of a physical substance without any change of temperature is called Latent heat of the substance.
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संबंधित प्रश्न
Differentiate between heat and temperature.
Name the law on which the principle of mixture is based.
The amount of heat energy required to convert 1 kg of ice at – 10℃ to water at 100℃ is 7,77,000 J. Calculate the specific latent heat of ice. Specific heat capacity of ice = 2100 J kg-1K-1, Specific heat capacity of water = 4200 J kg-1 K-1.
A piece of copper of mass 1 kg is dropped into 2 kg of water at 15°C. If the final temperature of the mixture is 40°C, calculate the intial temperature of copper.
100 g of ice at -10°C is heated. It is converted into steam. Calculate the quantity of heat which it has consumed. (Sp. heat of ice = 2100J/kg°C, sp. heat of water= 4200 J/kgK, sp. heat of water = 42000 J/kgK, sp. latent heat of ice = 2260000 J/kg).
A refrigerator converts 100 g of water at 20°C to ice at -10°C in 73.5 minutes. Calculate the average rate of heat extraction from water in watt. (Sp. heat of ice= 2100 J/kgK, sp. heat of water = 4200 J/kgK, Sp. latent heat of ice = 336000 J/kg.)
40 g of ice at -16°C is dropped into water at 0°C, when 4 g of water freezes into ice. If specific heat capacity of ice is 2100 J/kg°C, what will be the latent heat of fusion of ice?
250 g of water at 30 °C is present in a copper vessel of mass 50 g. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to 5 °C.
Specific latent heat of fusion of ice = 336 × 103 J kg-1
Specific heat capacity of copper vessel = 400 J kg-1 °C-1
Specific heat capacity of water = 4200 J kg-1 °C-1.
With the help of a neat diagram, explain the working of a calorimeter.
Write one characteristic property of the material chosen for making a calorimeter.
