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प्रश्न
Fill in the blanks in the table.
Principal | Rate of interest (p.c.p.a.) | Time | Interest | Amount |
...... | 6% | 4 years | 1200 | ...... |
उत्तर
Given:
Total interest (I) = 1200 rupess
Rate of interest (R) = 6%
Time (T) = 4 years
Formula:
Principal (P) = `("I"xx100)/("R"xx"T")`
Solution:
= `(1200xx100)/(6xx4)`
= 5000 rupees
Total Amount = P + I
= 5000 + 1200
= 6200 rupees
Principal | Rate of interest (p.c.p.a.) | Time | Interest | Amount |
5000 | 6% | 4 years | 1200 | 6200 |
संबंधित प्रश्न
Sonia had a recurring deposit account in a bank and deposited Rs. 600 per month for 2 1/2 years. If the rate of interest was 10% p.a., find the maturity value of this account.
A page from the ‘Savings Bank’ account of Priyanka is given below:
Date | Particulars |
Amount (Rs.) |
Amount deposited (Rs.) |
Balance (Rs.) |
03/04/2006 | B/F | 4000.00 | ||
05/04/2006 | By cash | 2000.00 | 6000.00 | |
18/04/2006 | By cheque | 6000.00 | 12000.00 | |
25/05/2006 | By cheque | 5000.00 | 7000.00 | |
30/05/2006 | By cash | 3000.00 | 10000.00 | |
20/07/2006 | By self | 4000.00 | 6000.00 | |
10/09/2006 | By cash | 2000.00 | 8000.00 | |
19/09/2006 | To cheque | 1000.00 | 7000.00 |
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A page from the Savings Bank Account of Mr Prateek is given below:
Date | Particulars | Withdrawal (In Rs.) |
Deposit (In Rs.) |
Balances (In Rs.) |
January 1st, 2006 | B/F | - | - | 1270 |
January 7th, 2006 | By Cheque | - | 2310 | 3580 |
March 9th, 2006 | To Self | 2000 | - | 1580 |
June 26th, 2006 | By Cash | - | 6200 | 7780 |
June 10th 2006 | To Cheque | 4500 | - | 3280 |
July 15th, 2006 | By Clearing | - | 2630 | 5910 |
October 18th, 2006 | To Cheque | 530 | - | 5380 |
October 27th, 2006 | To Self | 2690 | - | 2690 |
November 3rd, 2006 | By Cash | - | 1500 | 4190 |
December 6th, 2006 | To Cheque | 950 | - | 3240 |
December 23rd, 2006 | By Transfer | - | 2920 | 6260 |
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