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प्रश्न
Fill in the blanks:
y = ex .tan x
Differentiating w.r.t.x
`("d"y)/("d"x) = "d"/("d"x)("e"^x tan x)`
= `square "d"/("d"x) tanx + tan x "d"/("d"x) square`
= `square square + tan x square`
= `"e"^x [square + square]`
उत्तर
y = ex .tan x
Differentiating w.r.t.x
`("d"y)/("d"x) = "d"/("d"x)("e"^x tan x)`
= `"e"^x "d"/("d"x) tanx + tan x "d"/("d"x) "e"^x`
= `"e"^x sec^2x + tan x "e"^x`
= `"e"^x [sec^2x + tan x]`
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संबंधित प्रश्न
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Fill in the blanks:
y = `sinx/(x^2 + 2)`
Differentiating. w.r.t.x.
`("d"y)/("d"x) = (square "d"/("d"x) (sin x) - sin x "d"/("dx) square)/(x^2 + 2)^2`
= `(square square - sin x square)/(x^2 + 2)^2`
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Fill in the blanks:
y = (3x2 + 5) cos x
Differentiating w.r.t.x
`("d"y)/("d"x) = "d"/("d"x) [(3x^2 + 5) cos x]`
= `(3x^2 + 5) "d"/("d"x) [square] + cos x "d"/("d"x) [square]`
= `(3x^2 + 5) [square] + cos x [square]`
∴ `(dx)/("d"y) = (3x^2 + 5) [square] + [square] cos x`
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