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प्रश्न
Find:
the 18th term of the AP `sqrt(2), sqrt (18), sqrt(50), sqrt(98)`,...........
उत्तर
The given AP is `sqrt(2), sqrt (18), sqrt(50), sqrt(98)`,...........
This can be re-written as `sqrt(2), 3 sqrt(2) ,5 sqrt(2) ,7 sqrt(2),.........`
First term, a =`sqrt(2)`
Common difference, d = 3 `sqrt(2) - sqrt(2) = 2 sqrt(2)`
nth term of the AP an = a +(n-1) d = `sqrt(2) + (n-1) xx 2 sqrt(2)`
∴ 18th term of the AP a18 = `sqrt(2) +(18-1) xx 2 sqrt(2) = sqrt(2) = sqrt(2) + 34 sqrt(2) = 35 sqrt(2) = sqrt(2450) `
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