Question

Find the amount of silver liberated at the cathode if 0.500 A of current is passed through an AgNO₃ electrolyte for 1 hour. Atomic weight of silver is 107.9 g mol⁻¹.

Answer 1

Equivalent mass of silver, E_Ag = 107.9 g.............(∵ Ag is monoatomic)

The ECE of silver,

\[Z_{Ag} = \frac{E_{Ag}}{f} = \frac{107 . 9}{96500} = 0 . 001118\]

Using the formula, m = Zit, we get:-

m = 0.00118 × 0.500 × 3600

= 2.01 g

So, 2.01 g of silver is liberated.