Advertisements
Advertisements
प्रश्न
Find the common difference and write the next four terms of each of the following arithmetic progressions:
`-1, 1/4, 3/2 .....`
उत्तर
`-1, 1/4, 3/2 .....`
Here, first term (a1) =−1
Common difference (d) = `a_2 - a_1`
`= 1/4 - (-1)`
`=- (1 + 4)/4`
= 5/4
Now, we need to find the next four terms of the given A.P
That is we need to find `a_4, a_5, a_6, a_7`
So using the formula `a_n = a + (n -1)d`
Substituting n = 4, 5, 6, 7 in the above formula
Substituting n = 4, we get
`a_4 = -1 + (4 -1)(5/4)`
`a_4 = -1 + 15/4`
`a_4 = (-4 + 15)/4`
`a_4 = 11/4`
Substituting n = 5, we get
`a_5 = -1 + (5 - 1)(5/4)`
a_5 = - 1 + 5`
`a_5 = 4`
Substituting n = 6, we get
`a_6 = -1 + (6 - 1)(5/4)`
`a_6 = -1 + 25/4`
`a_6 = (-4 + 25)/4`
`a_6 = 21/4`
Substituting n = 7, we get
`a_7 = -1 + (7 -1) (5/4)`
`a_7 = -1 + 30/4`
`a_7 = (-4 + 30)/4`
`a_7 = 26/4`
Therefore, the common difference is `d = 5/4` and the next four term are `11/4 , 4. 21/4 , 26/4`
APPEARS IN
संबंधित प्रश्न
The sum of the 2nd and the 7th terms of an AP is 30. If its 15th term is 1 less than twice its 8th term, find the AP.
Write the first three terms in each of the sequences defined by the following
an = 3n + 2
Following are APs or not? If they form an A.P. find the common difference d and write three more terms:
`3, 3 + sqrt2, 3 + 2sqrt2, 3 + 3sqrt2`
Find the nth term of the A.P. 13, 8, 3, −2, ...
Find the 10th term of the A.P. −40, −15, 10, 35, ...
The ratio of 6th and 8th term of an A.P. is 7:9. Find the ratio of 9th term to 13th term
Choose the correct alternative answer for the following sub question
Find d of an A.P. whose first two terms are – 3 and 4
t19 = ? for the given A.P., 9, 4, −1, −6 ........
Activity :- Here a = 9, d = `square`
tn = a + (n − 1)d
t19 = 9 + (19 − 1) `square`
= 9 + `square`
= `square`
Verify that the following is an AP, and then write its next three terms.
`5, 14/3, 13/3, 4,...`
If –5, x, 3 are three consecutive terms of an A.P., then the value of x is ______.