Advertisements
Advertisements
प्रश्न
Find the cube of 2.1 .
योग
उत्तर
We have:
\[2 . 1 = \frac{21}{10}\]
Also,
\[\left( \frac{m}{n} \right)^3 = \frac{m^3}{n^3}\]
∴ \[\left( \frac{21}{10} \right)^3 = \frac{{21}^3}{{10}^3} = \frac{21 \times 21 \times 21}{10 \times 10 \times 10} = \frac{9261}{1000} = 9 . 261\]
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
The cube of a single-digit number may be a single-digit number.
Find the cubes of the following number by column method 56 .
Find the cube of \[\frac{7}{9}\] .
Find which of the following number is cube of rational number \[\frac{27}{64}\] .
Find the cube root of the following number −1728 × 216 .
Find the cube root of the following rational number \[\frac{- 39304}{- 42875}\] .
Simplify:
`root(3)(27/125)`
Find the cube of: -30
Which of the following numbers is not a perfect cube?
1m2 = ______ cm2.
