Advertisements
Advertisements
प्रश्न
Find the mean of each of the following frequency distributions
| Class interval | 10 - 30 | 30 - 50 | 50 - 70 | 70 - 90 | 90 - 110 | 110 - 130 |
| Frequency | 5 | 8 | 12 | 20 | 3 | 2 |
उत्तर
Let the assume mean A = 60
| Class interval | Mid value(x1) | d1 = x1 - 60 | `"u"_1=(x_1-60)/20` | f1 | f1u1 |
| 10 - 30 | 20 | -40 | -2 | 5 | -10 |
| 30 - 50 | 40 | -20 | -1 | 8 | -8 |
| 50 - 70 | 60 | 0 | 0 | 12 | 0 |
| 70 - 90 | 80 | 20 | 1 | 20 | 20 |
| 90 -110 | 100 | 40 | 2 | 3 | 6 |
| 110 - 130 | 120 | 60 | 3 | 2 | 6 |
| N = 50 | `sumf_1"u"_1=14` |
We have
A = 60, h = 20
Mean `=A+hxx(sumf_1"u"_1)/N`
`=60+20xx14/50`
`=60+280/50`
= 60 + 5.6
= 65.6
संबंधित प्रश्न
Calculate the mean for the following distribution:-
| x | 5 | 6 | 7 | 8 | 9 |
| f | 4 | 8 | 14 | 11 | 3 |
Find the mean marks per student, using assumed-mean method:
| Marks | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 |
| Number of Students |
12 | 18 | 27 | 20 | 17 | 6 |
If the mean of the following distribution is 27, find the value of p.
| Class | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
| Frequency | 8 | p | 12 | 13 | 10 |
There are three dealers A, B and C in Maharashtra. Suppose, the trade of each of them in september 2018 was as shown in the following table.
The rate of GST on each transaction was 5%.
Read the table and answer the questions below it.
| Dealer | GST collected on the sale |
GST paid at the time of purchase |
ITC | Tax paid to the Govt. |
Taxbalance with the Govt. |
| A | Rs.5000 | Rs. 6000 | Rs. 5000 | Rs. 0 | Rs. 1000 |
| B | Rs 5000 | Rs. 4000 | Rs. 4000 | Rs. 1000 | Rs. 0 |
| C | Rs.5000 | Rs. 5000 | Rs. 5000 | Rs. 0 | Rs. 0 |
(i) How much amount did the dealer A get by sale ?
(ii) For how much amount did the dealer B buy the articles ?
(iii) How much is the balance of CGST and SGST left with the government that was paid by A ?
If the arithmetic mean of x, x + 3, x + 6, x + 9, and x + 12 is 10, the x =
If Σfi = 25 and Σfixi = 100, then find the mean (`bar"x"`)
di is the deviation of xi from assumed mean a. If mean = `x+(sumf_id_i)/(sumf_i),` then x is ______.
In calculating the mean of grouped data, grouped in classes of equal width, we may use the formula `barx = a + (sumf_i d_i)/(sumf_i)` where a is the assumed mean. a must be one of the mid-points of the classes. Is the last statement correct? Justify your answer.
Find the mean of the following frequency distribution:
| Class: | 10 – 15 | 15 – 20 | 20 – 25 | 25 – 30 | 30 – 35 |
| Frequency: | 4 | 10 | 5 | 6 | 5 |
Which of the following cannot be determined graphically for a grouped frequency distribution?
