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प्रश्न
Find out the value of Kc for each of the following equilibria from the value of Kp:
\[\ce{2NOCl (g) ⇌ 2NO (g) + Cl2 (g)}\]; Kp= 1.8 × 10-2 at 500 K
उत्तर
The relation between Kp and Kc is given as:
Kp = Kc (RT)Δn
Here,
Δn = 3 - 2 = 1
R = 0.0831 barLmol-1K-1
T = 500 K
Kp = 1.8 × 10-2
Now,
Kp = Kc (RT) Δn
`=> 1.8 xx 10^(-2) = "K"_"c"(0.0831 xx 500)^1`
`=> "K"_"c" =((1.8 xx 10^(-2))/(0.0831 xx 500))`
`= 4.33 xx 10^(-4) ("approximately")`
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