Advertisements
Advertisements
प्रश्न
Find Q1, Q3, D8 and P67 of the following data:
| Size of Shares | 4 | 4.5 | 5 | 5.5 | 6 | 6.5 | 7 | 7.5 | 8 |
| Frequency | 10 | 18 | 22 | 25 | 40 | 15 | 10 | 8 | 7 |
उत्तर
| Size of Shares | Frequency | Cumulative Frequency |
| 4 | 10 | 10 |
| 4.5 | 18 | 28 |
| 5 | 22 | 50 |
| 5.5 | 25 | 75 |
| 6 | 40 | 115 |
| 6.5 | 15 | 130 |
| 7 | 10 | 140 |
| 7.5 | 8 | 148 |
| 8 | 7 | 155 |
| N = 155 |
Q1 = Size of `(("N" + 1)/4)^"th"` value
= Size of `((155 + 1)/4)^"th"` value
= Size of 39th value
Q1 = 5
Q3 = Size of `[3(("N" + 1)/4)]^"th"` value
= Size of `(3 xx 156/4)^"th"` value
= Size of 117th value
Q3 = 6.5
D8 = Size of `[8(("N" + 1)/10)]^"th"` value
= Size of `[8((155 + 1)/10)]^"th"` value
= Size of `(8 xx 156/10)^"th"` value
= Size of 124.8th value
D8 = 6.5
P67 = Size of `[67(("N" + 1)/100)]^"th"` value
= Size of `((67 xx 156)/100)^"th"` value
= Size of 104.52th value
P67 = 6
APPEARS IN
संबंधित प्रश्न
A man travelled by car for 3 days. He covered 480 km each day. On the first day, he drove for 10 hours at 48 km an hour. On the second day, he drove for 12 hours at 40 km an hour and for the last day he drove for 15 hours at 32 km. What is his average speed?
Calculate AM, GM and HM from the following data and also find its relationship:
| Marks: | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 |
| No. of students: | 5 | 10 | 25 | 30 | 20 | 10 |
When an observation in the data is zero, then its geometric mean is __________.
The correct relationship among A.M., G.M. and H.M. is
The median of 10, 14, 11, 9, 8, 12, 6 is
The mean of the values 11, 12, 13, 14 and 15 is
If the mean of 1, 2, 3, …, n is `(6"n")/11`, then the value of n is
Harmonic mean is better than other means if the data are for
The first quartile is also known as _________.
Define the mean.
