Advertisements
Advertisements
प्रश्न
Find the rate at which a sum of money will double itself in 3 years, if the interest is compounded annually.
उत्तर
Let the rate percent per annum be R.
Then,
\[A = P \left( 1 + \frac{R}{100} \right)^n \]
\[2P = P \left( 1 + \frac{R}{100} \right)^3 \]
\[ \left( 1 + \frac{R}{100} \right)^3 = 2\]
\[\left( 1 + \frac{R}{100} \right) = 1 . 2599\]
\[\frac{R}{100} = 0 . 2599\]
R = 25 . 99
Thus, the required rate is 25 . 99 % per annum.
APPEARS IN
संबंधित प्रश्न
Arif took a loan of Rs 80,000 from a bank. If the rate of interest is 10% per annum, find the difference in amounts he would be paying after `1 1/2` years if the interest is
(1) Compounded annually
(2) Compounded half yearly
Find the amount and the compound interest on Rs 10,000 for `1 1/2` years at 10% per annum, compounded half yearly. Would this interest be more than the interest he would get if it was compounded annually?
Find the compound interest when principal = Rs 3000, rate = 5% per annum and time = 2 years.
Find the amount of Rs 2400 after 3 years, when the interest is compounded annually at the rate of 20% per annum.
Amit borrowed Rs 16000 at \[17\frac{1}{2} \%\] per annum simple interest. On the same day, he lent it to Ashu at the same rate but compounded annually. What does he gain at the end of 2 years?
Rakesh lent out Rs 10000 for 2 years at 20% per annum, compounded annually. How much more he could earn if the interest be compounded half-yearly?
A sum of money deposited at 2% per annum compounded annually becomes Rs 10404 at the end of 2 years. Find the sum deposited.
Ashima took a loan of Rs 1,00,000 at 12% p.a. compounded half-yearly. She paid Rs 1,12,360. If (1.06)2 is equal to 1.1236, then the period for which she took the loan is ______.
Amount when interest is compounded annually is given by the formula ______.
If principal = Rs 1,00,000. rate of interest = 10% compounded half yearly. Find
- Interest for 6 months.
- Amount after 6 months.
- Interest for next 6 months.
- Amount after one year.