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प्रश्न
Find the slope of a line, correct of two decimals, whose inclination is 75°
उत्तर
SDlope of line = m = tan θ
= tan 75°
tan (75°) = (45° + 30°) = `("tan" 45° + "tan" 30°)/(1 - "tan" 45° "tan" 30°)`
= `(1 + 1/sqrt 3)/(1 - 1/sqrt 3) = (sqrt 3 + 1)/(sqrt - 1)`
= `2.73/0.73 = 273/73 = 3.73`
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