Advertisements
Advertisements
प्रश्न
Find the slope of a line passing through the points (x, 9) and (12, 6) is `(-1)/3 = ("y"_2 - "y"_1)/("x"_2 - "x"_1)`
उत्तर
Slope of line AB
⇒ `(-1)/3 = (6 - 9)/(12 -"x")`
⇒ x - 12 = -9
⇒ x = 3
APPEARS IN
संबंधित प्रश्न
A slope of a line is 3 and y-intercept is –4. Write the equation of a line
Without using the distance formula, show that the points A(4, −2), B(−4, 4) and C(10, 6) are the vertices of a right-angled triangle.
Determine whether the following point is collinear.
L(2, 5), M(3, 3), N(5, 1)
Determine whether the following point is collinear.
A(–4, 4), \[K\left( - 2, \frac{5}{2} \right),\] N (4, –2)
Show that A(4, –1), B(6, 0), C(7, –2) and D(5, –3) are vertices of a square.
Find the slope of a line, correct of two decimals, whose inclination is 45°
Find the slope of a line parallel to the given line x +3y = 7
Find the slope of a line parallel to the given line 4x-2y = 3
A line passing through the points (a, 2a) and (- 2, 3) is perpendicular to the line 4a + 3y + 5 = 0. Find the value of a.
Prove that A(4, 3), B(6, 4), C(5, 6) and D(3, 5) are the angular points of a square.
