Advertisements
Advertisements
प्रश्न
Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively.
उत्तर
TO FIND: The smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively.
L.C.M of 28 and 32.
`28=2^2xx7`
`32=2^5`
L.C.M of 28 ,and `32= 2^5xx7`
=224
Hence 224 is the least number which exactly divides 28 and 32 i.e. we will get a remainder of 0 in this case. But we need the smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively
Therefore
= 224-8-12
=204
Hence 204 is the smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively
APPEARS IN
संबंधित प्रश्न
If a and b are two odd positive integers such that a > b, then prove that one of the two numbers `(a+b)/2` and `(a-b)/2` is odd and the other is even.
Find the smallest number which when divides 28 and 32, leaving remainders 8 and 12 respectively.
Show that \[5 - 2\sqrt{3}\] is an irrational number.
Prove that \[2 - 3\sqrt{5}\] is an irrational number.
Every even integer is of the form 2m, where m is an integer (True/False).
Two numbers have 12 as their HCF and 350 as their LCM (True/False).
The exponent of 2 in the prime factorisation of 144, is
The smallest rational number by which \[\frac{1}{3}\] should be multiplied so that its decimal expansion terminates after one place of decimal, is
Express 429 as a product of its prime factors.
“The product of three consecutive positive integers is divisible by 6”. Is this statement true or false”? Justify your answer.
