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प्रश्न
Find the solution of the quadratic equation `3sqrt3x^2+10x+sqrt3=0`
उत्तर
The given quadratic equation is `3sqrt3x^2+10x+sqrt3=0`
` 3sqrt3^2+10x+sqrt3=0`
⇒`3sqrt3x^2+9x+x+sqrt3=0`
⇒` 3sqrt3x(x+sqrt3)+1(x+sqrt3)=0`
⇒`(x+sqrt3)(3sqrt3x+1)=0`
⇒` x+sqrt3=0 or 3sqrt3x+1=0`
⇒x=`-sqrt3 or x=-1/(3sqrt3)=-sqrt3/9`
Hence, `-sqrt3 and -sqrt3/9` are the solution of the given equation.
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