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प्रश्न
Find the 10th term of the G.P. :
`12, 4, 1 1/3, ................`
योग
उत्तर
Given G.P. : `12, 4, 1 1/3, ................`
Here,
Fisrt term, a = 12
Common ratio, r = `4/12 = 1/3`
Now, Tn = arn – 1
`\implies` T10 = `12xx(1/3)^9`
= `12 xx 1/19683`
= `4/6561`
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Geometric Progression - Finding Sum of Their First ‘N’ Terms
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