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प्रश्न
Find the angle between hour-hand and minute-hand in a clock at 10 : 10.
उत्तर
The angle between any two consecutive numbers of a clock is `(360°)/12` = 30°.
If the minute-hand is at 2 and hour-hand is at 10, angle between them is (4 × 30°) = 120°.
But at 10 past ten, i.e., at 10 : 10, the hour-hand has moved 10 minutes towards 11.
In 60 minutes, the hour-hand covers 30°.
In 10 minutes, hour hand covers `((10 xx 30)/60)^circ` = 5°
∴ The angle between the two hands of the clock at ten past ten = 120° – 5° = 115°.
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